derivative f(x)=2x^2-196ln(x)

Lösung

ableitung von

f (x) = 2 x^{2} - 196 ln (x)

4 x - \frac{196}{x}

Schritte zur Lösung

\frac{d}{d x} (2 x^{2} - 196 ln (x))

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{2}) - \frac{d}{d x} (196 ln (x))

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (196 ln (x)) = \frac{196}{x}

= 4 x - \frac{196}{x}

\int \frac{1}{( 16 - t ^{2} ) ^{\frac{3}{2}}} d t

\int_{- 1}^{3} 30 - 3 y^{2} - \frac{9}{2} d y

\frac{d y}{d x} = \frac{1}{1 + x ^{2}}

x \to 0 lim (\frac{5}{1 - e ^{\frac{1}{x}}})

16 y^{^{''}} + 11 y = 0