integral from 0 to 1 of (5x^4-4x^3)

解答

\int_{0}^{1} (5 x^{4} - 4 x^{3}) d x

0

求解步骤

\int_{0}^{1} 5 x^{4} - 4 x^{3} d x

使用积分加法定则:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{1} 5 x^{4} d x - \int_{0}^{1} 4 x^{3} d x

\int_{0}^{1} 5 x^{4} d x = 1

\int_{0}^{1} 4 x^{3} d x = 1

= 1 - 1

化简

= 0

t an g e n t g (x) = 2 x^{2}

h \to 0 lim (\frac{cos ( h )}{h})

\int \frac{3 x}{9 + x ^{2}} d x

d er i v a t i v e f (x) = 2^{2 x}

\int_{1}^{5} 2 r^{2} ln (r) d r