integral of x^2+2x+3

Lösung

\int x^{2} + 2 x + 3 d x

\frac{x ^{3}}{3} + x^{2} + 3 x + C

Schritte zur Lösung

\int x^{2} + 2 x + 3 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x^{2} d x + \int 2 x d x + \int 3 d x

\int x^{2} d x = \frac{x ^{3}}{3}

\int 2 x d x = x^{2}

\int 3 d x = 3 x

= \frac{x ^{3}}{3} + x^{2} + 3 x

Füge eine Konstante zur Lösung hinzu

= \frac{x ^{3}}{3} + x^{2} + 3 x + C

\frac{d}{d x} ((x^{2} + y^{2})^{6})

\frac{\partial}{\partial v} (\frac{u + v}{2})

y^{^{''''}} - 9 y^{^{''}} + 20 y = 0

\int \frac{10 3 5 x - 2}{3} d x

\int_{0}^{3} 1 + 16 x^{2} d x