What is the derivative of y= 3/(x^6)+1/(x^5)-7/(x^2) ?

The derivative of y= 3/(x^6)+1/(x^5)-7/(x^2) is -(18)/(x^7)-5/(x^6)+(14)/(x^3)

What is the first derivative of y= 3/(x^6)+1/(x^5)-7/(x^2) ?

The first derivative of y= 3/(x^6)+1/(x^5)-7/(x^2) is -(18)/(x^7)-5/(x^6)+(14)/(x^3)

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derivative of

y = \frac{3}{x ^{6}} + \frac{1}{x ^{5}} - \frac{7}{x ^{2}}

- \frac{18}{x ^{7}} - \frac{5}{x ^{6}} + \frac{14}{x ^{3}}

Solution steps

\frac{d}{d x} (\frac{3}{x ^{6}} + \frac{1}{x ^{5}} - \frac{7}{x ^{2}})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{3}{x ^{6}}) + \frac{d}{d x} (\frac{1}{x ^{5}}) - \frac{d}{d x} (\frac{7}{x ^{2}})

\frac{d}{d x} (\frac{3}{x ^{6}}) = - \frac{18}{x ^{7}}

\frac{d}{d x} (\frac{1}{x ^{5}}) = - \frac{5}{x ^{6}}

\frac{d}{d x} (\frac{7}{x ^{2}}) = - \frac{14}{x ^{3}}

= - \frac{18}{x ^{7}} - \frac{5}{x ^{6}} - (- \frac{14}{x ^{3}})

Simplify

= - \frac{18}{x ^{7}} - \frac{5}{x ^{6}} + \frac{14}{x ^{3}}

\frac{\partial}{\partial x} (x \cdot sin (4 \cdot y \cdot z^{4}))

t an g e n t f (x) = 2 x^{2} - 4 x, at x = - 1

t an g e n t f (x) = 4 x - x^{2}, (2, 5)

\int (2 x - 5)^{11} d x

\int_{- 1}^{2} \frac{x}{( x + 1 ) ^{2}} d x

What is the derivative of y= 3/(x^6)+1/(x^5)-7/(x^2) ?
The derivative of y= 3/(x^6)+1/(x^5)-7/(x^2) is -(18)/(x^7)-5/(x^6)+(14)/(x^3)
What is the first derivative of y= 3/(x^6)+1/(x^5)-7/(x^2) ?
The first derivative of y= 3/(x^6)+1/(x^5)-7/(x^2) is -(18)/(x^7)-5/(x^6)+(14)/(x^3)