en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular Calculus >

xy^'+xy=1-y

Solution

x y^{^{'}} + x y = 1 - y

Solution

y = \frac{1}{x} + \frac{c _{1}}{e ^{x} x}

Solution steps

x y^{'} (x) + x y = 1 - y

Solve linear ODE:

y = \frac{1}{x} + \frac{c _{1}}{e ^{x} x}

y = \frac{1}{x} + \frac{c _{1}}{e ^{x} x}

Graph

Popular Examples

(2xy^2-3y^3)dx+(7-3xy^2)dy=0

(2 x y^{2} - 3 y^{3}) d x + (7 - 3 x y^{2}) d y = 0

f (x) = x \cdot e^{\frac{1}{x}}

derivative of 9/(2x^2)

\frac{d}{d x} (\frac{9}{2 x ^{2}})

y^'=((t^2+ty+y^2))/(t^2)

y^{^{'}} = \frac{( t ^{2} + t y + y ^{2} )}{t ^{2}}

limit as h approaches 0 of 48+12h+h^2

h \to 0 lim (48 + 12 h + h^{2})

Frequently Asked Questions (FAQ)

What is the solution for xy^'+xy=1-y ?
The solution for xy^'+xy=1-y is y= 1/x+(c_{1})/(e^xx)