(\partial)/(\partial x)(xyz-z-sin(x+y))

解答

\frac{\partial}{\partial x} (x yz - z - sin (x + y))

yz - cos (x + y)

求解步骤

\frac{\partial}{\partial x} (x yz - z - sin (x + y))

将

y, z

视为常数

使用微分加减法定则:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x yz) - \frac{\partial}{\partial x} (z) - \frac{\partial}{\partial x} (sin (x + y))

\frac{\partial}{\partial x} (x yz) = yz

\frac{\partial}{\partial x} (z) = 0

\frac{\partial}{\partial x} (sin (x + y)) = cos (x + y)

= yz - 0 - cos (x + y)

化简

= yz - cos (x + y)

d er i v a t i v e f (x) = ln (\frac{x - 2}{x + 1})

\int x (7 - y)

\int \frac{1}{9 - 4 x ^{2}} d x

\int_{0}^{\infty} f (a + x) d x

n = 0 \sum \infty \frac{3}{( 1 + i ) ^{n}}