integral from 0 to 1 of 1/(sqrt(2-x^2))

Lösung

\int_{0}^{1} \frac{1}{2 - x ^{2}} d x

\frac{π}{4}

Dezimale

0.78539 \dots

Schritte zur Lösung

\int_{0}^{1} \frac{1}{2 - x ^{2}} d x

Trigonometrische Substitution anwenden

= \int_{0}^{\frac{π}{4}} 1 d u

Integral einer Konstanten :

\int a d x = a x

= [1 \cdot u]_{0}^{\frac{π}{4}}

Vereinfache

= [u]_{0}^{\frac{π}{4}}

Berechne die Grenzen:

\frac{π}{4}

= \frac{π}{4}

\int \frac{1}{x ^{2} + 4 x + 4} d x

\frac{\partial}{\partial y} (\frac{5 y}{x})

\frac{\partial}{\partial y} (2 x + y^{3})

\frac{d}{d x} ((4 x^{3} + 1)^{3})

a re a 5 - x^{2}, sin (x), - 2.384677, 2.0252116