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Beliebt Rechnen >

y^'=(t+y)^2-1

Lösung

y^{^{'}} = (t + y)^{2} - 1

Lösung

y = - \frac{1}{t + c _{1}} - t

Schritte zur Lösung

y^{'} (t) = (t + y)^{2} - 1

Solve using substitution:

y = - \frac{1}{t + c _{1}} - t

y = - \frac{1}{t + c _{1}} - t

Graph

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