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tangent f(x)=x^2,\at x=1.9

解答

切线

f (x) = x^{2}, at x = 1.9

解答

y = 3.8 x - 3.61

求解步骤

找到切点:

(1.9, 3.61)

计算

f (x) = x^{2}

的斜率:

\frac{df ( x )}{d x} = 2 x

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 3.8

找到斜率 m=

3.8

且穿过

(1.9, 3.61)

的直线:

y = 3.8 x - 3.61

y = 3.8 x - 3.61

作图

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