What is area sin(x)cos^2(x),4-4x,0.69275,0.92811 ?

The answer to area sin(x)cos^2(x),4-4x,0.69275,0.92811 is 0.09835…

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

area sin(x)cos^2(x),4-4x,0.69275,0.92811

area

sin (x) cos^{2} (x), 4 - 4 x, 0.69275, 0.92811

0.09835 \dots

Solution steps

Apply the area formula:

\int_{0.69275}^{0.92811} sin (x) cos^{2} (x) - (4 - 4 x) d x

Solve

\int_{0.69275}^{0.92811} sin (x) cos^{2} (x) - (4 - 4 x) d x : 0.09835 \dots

The area is:

= 0.09835 \dots

\frac{d y}{d x} + \frac{3 y}{x} + 2 = 3 x, y (1) = 1

\frac{d}{d x} (3 x^{2} + 5 x - 2)

\int 2 tan^{5} (4 x) d x

y^{^{''}} + 4 y^{^{'}} + 5 y = 35 e - 4 x

\frac{2}{( 4 s ^{2} - 8 s )}

What is area sin(x)cos^2(x),4-4x,0.69275,0.92811 ?
The answer to area sin(x)cos^2(x),4-4x,0.69275,0.92811 is 0.09835…