What is the tangent of-4x^2-7x ?

The tangent of-4x^2-7x is y=(-8a_{0}-7)x+4a_{0}^2

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tangent of-4x^2-7x

tangent of

- 4 x^{2} - 7 x

y = (- 8 a_{0} - 7) x + 4 a_{0}^{2}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, - 4 a_{0}^{2} - 7 a_{0})

Find the slope of

y = - 4 x^{2} - 7 x : \frac{d y}{d x} = - 8 x - 7

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 8 a_{0} - 7

Find the line with slope m=

- 8 a_{0} - 7

and passing through

(a_{0}, - 4 a_{0}^{2} - 7 a_{0}) : y = (- 8 a_{0} - 7) x + 4 a_{0}^{2}

y = (- 8 a_{0} - 7) x + 4 a_{0}^{2}

f (4) = 10 x - 13

\frac{d}{d x} (x e^{r x})

x^{2} y^{^{''}} + 2 x y^{^{'}} - 2 y = 0

f (x) = 9 e^{x} 12 x, at x = 0

\int (4 x + 2) (x^{2} + x - 1)^{5} d x

What is the tangent of-4x^2-7x ?
The tangent of-4x^2-7x is y=(-8a_{0}-7)x+4a_{0}^2