What is the derivative of x^2+4x+3 ?

The derivative of x^2+4x+3 is 2x+4

What is the first derivative of x^2+4x+3 ?

The first derivative of x^2+4x+3 is 2x+4

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\frac{d}{d x} (x^{2} + 4 x + 3)

2 x + 4

Solution steps

\frac{d}{d x} (x^{2} + 4 x + 3)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (4 x) + \frac{d}{d x} (3)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (4 x) = 4

\frac{d}{d x} (3) = 0

= 2 x + 4 + 0

Simplify

= 2 x + 4

x \to 1 - lim (\frac{1}{x})

\int \frac{8}{( x - 2 ) ( x + 6 )} d x

d er i v a t i v e y = 9 x^{2} - x^{e}

\frac{d}{d x} (- C x - d)

\frac{\partial}{\partial x} (x^{2} y^{2} e^{6 x y})

What is the derivative of x^2+4x+3 ?
The derivative of x^2+4x+3 is 2x+4
What is the first derivative of x^2+4x+3 ?
The first derivative of x^2+4x+3 is 2x+4