zs

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

受欢迎的微积分 >

tangent f(x)= x/(x^2+49)

解答

切线

f (x) = \frac{x}{x ^{2} + 49}

解答

y = \frac{- a _{0}^{2} + 49}{( a _{0}^{2} + 49 ) ^{2}} x + \frac{2 a _{0}^{3}}{( a _{0}^{2} + 49 ) ^{2}}

求解步骤

计算在一般点

x = a_{0}

的切线

找到切点:

(a_{0}, \frac{a _{0}}{a _{0}^{2} + 49})

计算

f (x) = \frac{x}{x ^{2} + 49}

的斜率:

\frac{df ( x )}{d x} = \frac{- x ^{2} + 49}{( x ^{2} + 49 ) ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = \frac{- a _{0}^{2} + 49}{( a _{0}^{2} + 49 ) ^{2}}

找到斜率 m=

\frac{- a _{0}^{2} + 49}{( a _{0}^{2} + 49 ) ^{2}}

且穿过

(a_{0}, \frac{a _{0}}{a _{0}^{2} + 49})

的直线:

y = \frac{- a _{0}^{2} + 49}{( a _{0}^{2} + 49 ) ^{2}} x + \frac{2 a _{0}^{3}}{( a _{0}^{2} + 49 ) ^{2}}

y = \frac{- a _{0}^{2} + 49}{( a _{0}^{2} + 49 ) ^{2}} x + \frac{2 a _{0}^{3}}{( a _{0}^{2} + 49 ) ^{2}}

作图

流行的例子

derivative of 2ln|x-e^x|

\frac{d}{d x} (2 ln ∣ x - e^{x} ∣)

(\partial)/(\partial y)(-1/(ln(10)(x-y)))

\frac{\partial}{\partial y} (- \frac{1}{ln ( 10 ) ( x - y )})

f(x)= 8/(sin(x)+cos(x))

f (x) = \frac{8}{sin ( x ) + cos ( x )}

面积 f(x)=x^2-12,g(x)=x-6,[2sqrt(3),6]

a re a f (x) = x^{2} - 12, g (x) = x - 6, [23, 6]

integral from 0 to 1 of x-sqrt(x)

\int_{0}^{1} x - x d x