What is the integral of x(x^2+1)^3 ?

The integral of x(x^2+1)^3 is (x^8)/8+(x^6)/2+(3x^4)/4+(x^2)/2+C

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integral of x(x^2+1)^3

\int x (x^{2} + 1)^{3} d x

\frac{x ^{8}}{8} + \frac{x ^{6}}{2} + \frac{3 x ^{4}}{4} + \frac{x ^{2}}{2} + C

Solution steps

\int x (x^{2} + 1)^{3} d x

Expand

x (x^{2} + 1)^{3} : x^{7} + 3 x^{5} + 3 x^{3} + x

= \int x^{7} + 3 x^{5} + 3 x^{3} + x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x^{7} d x + \int 3 x^{5} d x + \int 3 x^{3} d x + \int x d x

\int x^{7} d x = \frac{x ^{8}}{8}

\int 3 x^{5} d x = \frac{x ^{6}}{2}

\int 3 x^{3} d x = \frac{3 x ^{4}}{4}

\int x d x = \frac{x ^{2}}{2}

= \frac{x ^{8}}{8} + \frac{x ^{6}}{2} + \frac{3 x ^{4}}{4} + \frac{x ^{2}}{2}

Add a constant to the solution

= \frac{x ^{8}}{8} + \frac{x ^{6}}{2} + \frac{3 x ^{4}}{4} + \frac{x ^{2}}{2} + C

What is the integral of x(x^2+1)^3 ?
The integral of x(x^2+1)^3 is (x^8)/8+(x^6)/2+(3x^4)/4+(x^2)/2+C