What is the solution for dy=(x-2y(cot(2x)))dx ?

The solution for dy=(x-2y(cot(2x)))dx is y=-(xcos(2x))/(2sin(2x))+1/4+(c_{1})/(sin(2x))

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dy=(x-2y(cot(2x)))dx

d y = (x - 2 y (cot (2 x))) d x

y = - \frac{x cos ( 2 x )}{2 sin ( 2 x )} + \frac{1}{4} + \frac{c _{1}}{sin ( 2 x )}

Solution steps

d y = (x - 2 y (cot (2 x))) d x

Solve linear ODE:

y = - \frac{x cos ( 2 x )}{2 sin ( 2 x )} + \frac{1}{4} + \frac{c _{1}}{sin ( 2 x )}

y = - \frac{x cos ( 2 x )}{2 sin ( 2 x )} + \frac{1}{4} + \frac{c _{1}}{sin ( 2 x )}

What is the solution for dy=(x-2y(cot(2x)))dx ?
The solution for dy=(x-2y(cot(2x)))dx is y=-(xcos(2x))/(2sin(2x))+1/4+(c_{1})/(sin(2x))