What is the derivative of-6sin(2x) ?

The derivative of-6sin(2x) is -12cos(2x)

What is the first derivative of-6sin(2x) ?

The first derivative of-6sin(2x) is -12cos(2x)

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\frac{d}{d x} (- 6 sin (2 x))

- 12 cos (2 x)

Solution steps

\frac{d}{d x} (- 6 sin (2 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 6 \frac{d}{d x} (sin (2 x))

Apply the chain rule:

cos (2 x) \frac{d}{d x} (2 x)

= cos (2 x) \frac{d}{d x} (2 x)

\frac{d}{d x} (2 x) = 2

= - 6 cos (2 x) \cdot 2

Simplify

= - 12 cos (2 x)

\frac{d}{d x} (\frac{81 + x ^{2}}{3} + \frac{15 - x}{5})

\frac{\partial}{\partial x} (- 5 y cos (- 9 x))

x \to \infty lim (7 - e^{x})

\int_{0}^{1} \frac{16 x}{8 x ^{2} + 2} d x

\int tan^{3} (x) sec^{- \frac{1}{2}} (x) d x

What is the derivative of-6sin(2x) ?
The derivative of-6sin(2x) is -12cos(2x)
What is the first derivative of-6sin(2x) ?
The first derivative of-6sin(2x) is -12cos(2x)