d/(dt)(e^{-it})

Lösung

\frac{d}{d t} (e^{- i t})

- sin (t) - i cos (t)

Schritte zur Lösung

\frac{d}{d t} (e^{- i t})

Vereinfache

e^{- i t} : cos (t) - i sin (t)

= \frac{d}{d t} (cos (t) - i sin (t))

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (cos (t)) - \frac{d}{d t} (i sin (t))

\frac{d}{d t} (cos (t)) = - sin (t)

\frac{d}{d t} (i sin (t)) = i cos (t)

= - sin (t) - i cos (t)

x \to 6 lim (c x^{2} + 9 x)

\frac{\partial}{\partial u} (\frac{v - u}{2})

s l o p e (- 3, - 8), (5, 6)

\frac{\partial}{\partial x} (x^{2} y + 2 y^{2} - 6 x + 3 y - 4)

\int \frac{2}{1 - x ^{2}} d x