integral from-3 to 4 of ((y+12)-(y^2))

解答

\int_{- 3}^{4} ((y + 12) - (y^{2})) d y

\frac{343}{6}

十进制

57.16666 \dots

求解步骤

\int_{- 3}^{4} y + 12 - y^{2} d y

使用积分加法定则:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 3}^{4} y d y + \int_{- 3}^{4} 12 d y - \int_{- 3}^{4} y^{2} d y

\int_{- 3}^{4} y d y = \frac{7}{2}

\int_{- 3}^{4} 12 d y = 84

\int_{- 3}^{4} y^{2} d y = \frac{91}{3}

= \frac{7}{2} + 84 - \frac{91}{3}

化简

\frac{7}{2} + 84 - \frac{91}{3} : \frac{343}{6}

= \frac{343}{6}

y^{^{''}} + 7 y^{^{'}} + 6 y = 0

d er i v a t i v e f (x) = 2 (x)^{3} ln (x)

x \to - 2 lim (\frac{x ^{2} + 4}{x + 2})

a re a y = - x^{2} + 10, y = - 1.5 x + 7

\frac{d}{d x} (\frac{x ^{2} - x ^{4}}{8})