y^{''}+6y^'+15y=0

Lösung

y^{^{''}} + 6 y^{^{'}} + 15 y = 0

y = e^{- 3 t} (c_{1} cos (6 t) + c_{2} sin (6 t))

Schritte zur Lösung

y^{''} (t) + 6 y^{'} (t) + 15 y = 0

Solve linear ODE:

y = e^{- 3 t} (c_{1} cos (6 t) + c_{2} sin (6 t))

y = e^{- 3 t} (c_{1} cos (6 t) + c_{2} sin (6 t))

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