xy^'-2y=7x^2

解答

x y^{^{'}} - 2 y = 7 x^{2}

y = 7 ln (x) x^{2} + c_{1} x^{2}

求解步骤

x y^{'} (x) - 2 y = 7 x^{2}

求解线性方程:

y = 7 ln (x) x^{2} + c_{1} x^{2}

y = 7 ln (x) x^{2} + c_{1} x^{2}

d er i v a t i v e \frac{9 - x ^{2}}{4 x}

d er i v a t i v e f (x) = (x + 1) (2 x - 1)

\int_{0}^{\frac{π}{8}} sin^{5} (4 x) d x

y^{^{'''}} + y^{^{''}} + 3 y^{^{'}} - 5 y = 0

\int \frac{sin ( 2 x )}{2 sin ( x )} d x