xy^'-y=x,y(1)=10

Lösung

x y^{^{'}} - y = x, y (1) = 10

y = ln (x) x + 10 x

Schritte zur Lösung

x y^{'} (x) - y = x

Solve linear ODE:

y = ln (x) x + 10 x

y = ln (x) x + 10 x

\int_{0}^{2} π (3 x^{2})^{2} d x

\frac{\partial}{\partial x} (4 x^{2} + 3 y^{4})

x \to 1 - lim (\frac{1}{x} - 1)

y^{^{''}} + 9 y = 3 sec (3 t)

f (x) = cos (x^{2}) \cdot 2 x