derivative of sqrt(2x)+\sqrt[3]{3x}

Lösung

\frac{d}{d x} (2 x + 3 3 x)

\frac{1}{2 x} + \frac{1}{3 ^{\frac{2}{3}} x ^{\frac{2}{3}}}

Schritte zur Lösung

\frac{d}{d x} (2 x + 3 3 x)

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x) + \frac{d}{d x} (3 3 x)

\frac{d}{d x} (2 x) = \frac{1}{2 x}

\frac{d}{d x} (3 3 x) = \frac{1}{3 ^{\frac{2}{3}} x ^{\frac{2}{3}}}

= \frac{1}{2 x} + \frac{1}{3 ^{\frac{2}{3}} x ^{\frac{2}{3}}}

a re a 3 x, \frac{1}{x}, 1, 8

\frac{\partial}{\partial x} (x^{2} + 1)

t an g e n t f (x) = 2 x e^{x} cos (x), at x = 0

\int_{0}^{2} sin (x) + e^{x} d x

\frac{d}{d x} ((\frac{1}{x})^{\frac{1}{2}})