What is the derivative of 4x-x^3 ?

The derivative of 4x-x^3 is 4-3x^2

What is the first derivative of 4x-x^3 ?

The first derivative of 4x-x^3 is 4-3x^2

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\frac{d}{d x} (4 x - x^{3})

4 - 3 x^{2}

Solution steps

\frac{d}{d x} (4 x - x^{3})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4 x) - \frac{d}{d x} (x^{3})

\frac{d}{d x} (4 x) = 4

\frac{d}{d x} (x^{3}) = 3 x^{2}

= 4 - 3 x^{2}

\frac{\partial}{\partial x} (8 x y^{2} - 8 x^{3} y)

\int \frac{1}{sin ^{4} ( x ) cos ^{2} ( x )} d x

\frac{\partial}{\partial x} (x^{6} + 2^{y} + x^{y})

\frac{d}{d x} (x (x^{2} + 3)^{\frac{1}{2}})

\frac{\partial}{\partial y} (x^{3} - 3 x + 3 x y^{2})

What is the derivative of 4x-x^3 ?
The derivative of 4x-x^3 is 4-3x^2
What is the first derivative of 4x-x^3 ?
The first derivative of 4x-x^3 is 4-3x^2