derivative sin(θ)cos(θ)

Lösung

ableitung von

sin (θ) cos (θ)

cos (2 θ)

Schritte zur Lösung

\frac{d}{d θ} (sin (θ) cos (θ))

Wende die Produktregel an:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = sin (θ), g = cos (θ)

= \frac{d}{d θ} (sin (θ)) cos (θ) + \frac{d}{d θ} (cos (θ)) sin (θ)

\frac{d}{d θ} (sin (θ)) = cos (θ)

\frac{d}{d θ} (cos (θ)) = - sin (θ)

= cos (θ) cos (θ) + (- sin (θ)) sin (θ)

Vereinfache

cos (θ) cos (θ) + (- sin (θ)) sin (θ) : cos (2 θ)

= cos (2 θ)

\int - sec (x) d x

x \to - 27 lim (\frac{6}{x + 27})

\int_{0}^{- 0.4} 400 x d x

\frac{d}{d x} (\frac{- 2 x ^{3} - 1}{( x ^{3} - 1 ) ^{2}})

\int y^{6} d y