derivative of x-y+1

解答

\frac{d}{d x} (x - y + 1)

- \frac{d y}{d x} + 1

求解步骤

\frac{d}{d x} (x - y + 1)

使用微分加减法定则:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d x}{d x} - \frac{d y}{d x} + \frac{d}{d x} (1)

\frac{d x}{d x} = 1

\frac{d}{d x} (1) = 0

= 1 - \frac{d y}{d x} + 0

化简

= - \frac{d y}{d x} + 1

\frac{\partial}{\partial y} (4 y^{2})

\frac{d}{d x} (ln (5 x^{2}))

s l o p e (x^{2} + y^{2})^{2} = 4 x^{2} y

\frac{d}{d x} (3 x^{2} sin (5 x))

\frac{d}{d x} (arctanh (x))