limit as θ approaches 0 of (sin^2(θ))/θ

解答

θ \to 0 lim (\frac{sin ^{2} ( θ )}{θ})

0

求解步骤

θ \to 0 lim (\frac{sin ^{2} ( θ )}{θ})

使用洛必达法则

= θ \to 0 lim (\frac{sin ( 2 θ )}{1})

代入值

θ = 0

= \frac{sin ( 2 \cdot 0 )}{1}

化简

\frac{sin ( 2 \cdot 0 )}{1} : 0

= 0

\frac{d}{d x} ((5 x^{6} + 4 x^{3})^{4})

\frac{d}{d x} (ln (9 - x^{2}))

t an g e n t f (x) = (9 x^{9} - 9) (8 - 8 x^{8}), at x = 0

\int - \frac{1}{sin ( x )} d x

\int_{0}^{4} x e^{- a x} d x