sum from n=2 to infinity of 2/(n^2-n)

Lösung

n = 2 \sum \infty \frac{2}{n ^{2} - n}

2

Schritte zur Lösung

n = 2 \sum \infty \frac{2}{n ^{2} - n}

Wende die Regel der konstanten Multiplikation:

\sum c \cdot a_{n} = c \cdot \sum a_{n}

= 2 \cdot n = 2 \sum \infty \frac{1}{n ^{2} - n}

Teleskopreihen-Test anwenden:

1

= 2 \cdot 1

Vereinfache

= 2

\frac{d}{d x} (a + \frac{b}{r ( x ) ( x ) ^{2}})^{3}

\int_{0}^{2} \frac{1}{x ^{2} + x - 6} d x

x \to 11 lim (10)

\int (4 sec^{3} (x)) d x

n = - 4 \sum \infty (\frac{- 4}{9})^{n}