What is the sum from n=1 to infinity of 1/(5^n+7) ?

The sum from n=1 to infinity of 1/(5^n+7) is converges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

sum from n=1 to infinity of 1/(5^n+7)

n = 1 \sum \infty \frac{1}{5 ^{n} + 7}

converges

Solution steps

n = 1 \sum \infty \frac{1}{5 ^{n} + 7}

Apply Series Ratio Test:

converges

= converges

x^{2} y^{^{''}} + 3 x y^{^{'}} = 2

\frac{d}{d x} (ln (8 x^{2} + 7 x + 2))

\int_{1}^{3} \frac{7}{16 - x ^{2}} d x

\int \frac{26 x ^{3} - 52 x ^{2} + 7}{x ^{2} - 2 x} d x

d er i v a t i v e ln (9)

What is the sum from n=1 to infinity of 1/(5^n+7) ?
The sum from n=1 to infinity of 1/(5^n+7) is converges