What is (\partial)/(\partial x)(y^2-x^2-x^3) ?

The answer to (\partial)/(\partial x)(y^2-x^2-x^3) is -3x^2-2x

(\partial)/(\partial x)(y^2-x^2-x^3)

\frac{\partial}{\partial x} (y^{2} - x^{2} - x^{3})

- 3 x^{2} - 2 x

Solution steps

\frac{\partial}{\partial x} (y^{2} - x^{2} - x^{3})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (y^{2}) - \frac{\partial}{\partial x} (x^{2}) - \frac{\partial}{\partial x} (x^{3})

\frac{\partial}{\partial x} (y^{2}) = 0

\frac{\partial}{\partial x} (x^{2}) = 2 x

\frac{\partial}{\partial x} (x^{3}) = 3 x^{2}

= 0 - 2 x - 3 x^{2}

Simplify

= - 3 x^{2} - 2 x

\int_{0}^{1} 2 1 - x^{2} d x

t a y l or (x^{2} + 1) e^{x - 1}, 1

\frac{d y}{d x} = \frac{( 4 sec ( y ) )}{( x + 3 ) ^{2}}

\frac{d}{d x} (\frac{( x ^{4} - 5 x ^{3} + x )}{x ^{2}})

\frac{d}{d x} (e^{4 x} tan (x^{5} - 4 x^{4}))

What is (\partial)/(\partial x)(y^2-x^2-x^3) ?
The answer to (\partial)/(\partial x)(y^2-x^2-x^3) is -3x^2-2x