y^'=((y^3+1))/((3xy^2))

Lösung

y^{^{'}} = \frac{( y ^{3} + 1 )}{( 3 x y ^{2} )}

y = 3 c_{1} x - 1

Schritte zur Lösung

y^{'} (x) = \frac{( y ^{3} + 1 )}{( 3 x y ^{2} )}

Solve separable ODE:

y = 3 c_{1} x - 1

y = 3 c_{1} x - 1

x \to + 1 lim (\frac{1 - ∣ x ∣}{x - 1})

\int \frac{x ^{3}}{1 + x ^{4}} d x

y^{^{'}} - y + x^{2} = 0

\int_{3}^{6} \frac{1}{x ^{2} - 1} d x

\int x^{\frac{2}{9}} d x