What is (\partial)/(\partial y)(8y-4x) ?

The answer to (\partial)/(\partial y)(8y-4x) is 8

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(\partial)/(\partial y)(8y-4x)

\frac{\partial}{\partial y} (8 y - 4 x)

8

Solution steps

\frac{\partial}{\partial y} (8 y - 4 x)

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (8 y) - \frac{\partial}{\partial y} (4 x)

\frac{\partial}{\partial y} (8 y) = 8

\frac{\partial}{\partial y} (4 x) = 0

= 8 - 0

Simplify

= 8

\int_{0}^{1} x^{\frac{3}{2}} d x

d er i v a t i v e y = e^{(4 x^{3} + 5)^{2}}

\int (1 + x y) e^{x y} d x

\int x (2^{x^{2}}) d x

(5 x)^{^{'}}

What is (\partial)/(\partial y)(8y-4x) ?
The answer to (\partial)/(\partial y)(8y-4x) is 8