What is the derivative of 81m^8+2m^4+1 ?

The derivative of 81m^8+2m^4+1 is 648m^7+8m^3

What is the first derivative of 81m^8+2m^4+1 ?

The first derivative of 81m^8+2m^4+1 is 648m^7+8m^3

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derivative of

81 m^{8} + 2 m^{4} + 1

648 m^{7} + 8 m^{3}

Solution steps

\frac{d}{d m} (81 m^{8} + 2 m^{4} + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d m} (81 m^{8}) + \frac{d}{d m} (2 m^{4}) + \frac{d}{d m} (1)

\frac{d}{d m} (81 m^{8}) = 648 m^{7}

\frac{d}{d m} (2 m^{4}) = 8 m^{3}

\frac{d}{d m} (1) = 0

= 648 m^{7} + 8 m^{3} + 0

Simplify

= 648 m^{7} + 8 m^{3}

d er i v a t i v e arcsin (4 x + 1)

\frac{d}{d x} (\frac{x}{2 x ^{2} + 1})

\int (7 + x^{5})^{6} 5 x^{4} d x

y^{^{''}} - 16 y^{^{'}} + 64 y = 8 t^{6} e^{8 t}

\frac{d}{d x} (x^{2} + 17)

What is the derivative of 81m^8+2m^4+1 ?
The derivative of 81m^8+2m^4+1 is 648m^7+8m^3
What is the first derivative of 81m^8+2m^4+1 ?
The first derivative of 81m^8+2m^4+1 is 648m^7+8m^3