integral of (x+3)/(x^2+16)

Lösung

\int \frac{x + 3}{x ^{2} + 16} d x

\frac{1}{2} ln x^{2} + 16 + \frac{3}{4} arctan (\frac{x}{4}) + C

Schritte zur Lösung

\int \frac{x + 3}{x ^{2} + 16} d x

Multipliziere aus

\frac{x + 3}{x ^{2} + 16} : \frac{x}{x ^{2} + 16} + \frac{3}{x ^{2} + 16}

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{x}{x ^{2} + 16} d x + \int \frac{3}{x ^{2} + 16} d x

\int \frac{x}{x ^{2} + 16} d x = \frac{1}{2} ln x^{2} + 16

\int \frac{3}{x ^{2} + 16} d x = \frac{3}{4} arctan (\frac{x}{4})

= \frac{1}{2} ln x^{2} + 16 + \frac{3}{4} arctan (\frac{x}{4})

Füge eine Konstante zur Lösung hinzu

= \frac{1}{2} ln x^{2} + 16 + \frac{3}{4} arctan (\frac{x}{4}) + C

t \to 8 lim (\frac{t ( t - 5 ) - 24}{t ^{2} - 8 t})

z \to 2 i lim (\frac{1 - z}{1 + z})

n = 1 \sum \infty 3 r^{n}

x \to 3 - lim (2 x + 5)

x \to \infty lim (4 x + 14)