What is the derivative of-4*3^x ?

The derivative of-4*3^x is -4*3^xln(3)

What is the first derivative of-4*3^x ?

The first derivative of-4*3^x is -4*3^xln(3)

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\frac{d}{d x} (- 4 \cdot 3^{x})

- 4 \cdot 3^{x} ln (3)

Solution steps

\frac{d}{d x} (- 4 \cdot 3^{x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 4 \frac{d}{d x} (3^{x})

Apply the derivative exponent rule:

\frac{d}{d x} (a^{x}) = a^{x} ln (a)

= - 4 \cdot 3^{x} ln (3)

\frac{d}{d x} (\frac{( x + 1 ) ( x - 2 )}{x ^{2} - 5 x + 1})

\frac{d y}{d x} + 3 y = e^{x}

t a y l or 1 + e^{x}

t an g e n t f (x) = 5 x^{2}, at x = 2

\frac{d}{d x} (\frac{1 + sin ( x )}{x cos ( x )})

What is the derivative of-4*3^x ?
The derivative of-4*3^x is -4*3^xln(3)
What is the first derivative of-4*3^x ?
The first derivative of-4*3^x is -4*3^xln(3)