What is the integral of (-6x^6-2x^3-4) ?

The integral of (-6x^6-2x^3-4) is -(6x^7)/7-(x^4)/2-4x+C

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integral of (-6x^6-2x^3-4)

\int (- 6 x^{6} - 2 x^{3} - 4) d x

- \frac{6 x ^{7}}{7} - \frac{x ^{4}}{2} - 4 x + C

Solution steps

\int - 6 x^{6} - 2 x^{3} - 4 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int 6 x^{6} d x - \int 2 x^{3} d x - \int 4 d x

\int 6 x^{6} d x = \frac{6 x ^{7}}{7}

\int 2 x^{3} d x = \frac{x ^{4}}{2}

\int 4 d x = 4 x

= - \frac{6 x ^{7}}{7} - \frac{x ^{4}}{2} - 4 x

Add a constant to the solution

= - \frac{6 x ^{7}}{7} - \frac{x ^{4}}{2} - 4 x + C

a re a y = x^{2} - 39, y = 9 - 2 x

\frac{\partial}{\partial y} (12 x y)

d er i v a t i v e 10 sin (t)

\int x tan^{2} (2 x) d x

d er i v a t i v e x^{4} e^{x}

What is the integral of (-6x^6-2x^3-4) ?
The integral of (-6x^6-2x^3-4) is -(6x^7)/7-(x^4)/2-4x+C