What is the solution for y^2(dy)/(dx)+y^3=1 ?

The solution for y^2(dy)/(dx)+y^3=1 is y=\sqrt[3]{-e^{-3x-c_{1}}+1}

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y^2(dy)/(dx)+y^3=1

y^{2} \frac{d y}{d x} + y^{3} = 1

y = 3 - e^{- 3 x - c_{1}} + 1

Solution steps

y^{2} \frac{d y}{d x} + y^{3} = 1

Solve separable ODE:

y = 3 - e^{- 3 x - c_{1}} + 1

y = 3 - e^{- 3 x - c_{1}} + 1

\frac{d}{d x} (\frac{x ^{2} + 3}{x ^{2} - 3})

n = 1 \sum \infty \frac{n ^{2}}{5 ^{n}}

\int x^{2} - 4 d x

\frac{d}{d x} (\frac{2 - x}{x ^{2}})

\frac{d}{d x} (\frac{3 - 4 x}{x ^{2} + 1})

What is the solution for y^2(dy)/(dx)+y^3=1 ?
The solution for y^2(dy)/(dx)+y^3=1 is y=\sqrt[3]{-e^{-3x-c_{1}}+1}