What is the derivative of y=sin^2(x) ?

The derivative of y=sin^2(x) is sin(2x)

What is the first derivative of y=sin^2(x) ?

The first derivative of y=sin^2(x) is sin(2x)

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derivative of

y = sin^{2} (x)

sin (2 x)

Solution steps

\frac{d}{d x} (sin^{2} (x))

Apply the chain rule:

2 sin (x) \frac{d}{d x} (sin (x))

= 2 sin (x) \frac{d}{d x} (sin (x))

\frac{d}{d x} (sin (x)) = cos (x)

= 2 sin (x) cos (x)

Use the Double Angle identity:

2 sin (x) cos (x) = sin (2 x)

= sin (2 x)

\int 4 sin (4 x) d x

a re a \frac{6}{x}, 3 x, \frac{x}{3}

\frac{d}{d x} (sec^{3} (2 x))

\int_{- 7}^{- 5} \frac{3}{( x + 6 ) ^{\frac{8}{11}}} d x

t an g e n t f (x) = 1 - tan (x), at x = - \frac{π}{4}

What is the derivative of y=sin^2(x) ?
The derivative of y=sin^2(x) is sin(2x)
What is the first derivative of y=sin^2(x) ?
The first derivative of y=sin^2(x) is sin(2x)