What is the solution for e^{t^2}y^'+(t+ty^2)=0 ?

The solution for e^{t^2}y^'+(t+ty^2)=0 is y=tan(1/2 e^{-t^2}+c_{1})

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e^{t^2}y^'+(t+ty^2)=0

e^{t^{2}} y^{^{'}} + (t + t y^{2}) = 0

y = tan (\frac{1}{2} e^{- t^{2}} + c_{1})

Solution steps

e^{t^{2}} y^{'} (t) + (t + t y^{2}) = 0

Solve separable ODE:

y = tan (\frac{1}{2} e^{- t^{2}} + c_{1})

y = tan (\frac{1}{2} e^{- t^{2}} + c_{1})

What is the solution for e^{t^2}y^'+(t+ty^2)=0 ?
The solution for e^{t^2}y^'+(t+ty^2)=0 is y=tan(1/2 e^{-t^2}+c_{1})