3y^'-9x^2=0

解答

3 y^{^{'}} - 9 x^{2} = 0

y = x^{3} + c_{1}

求解步骤

3 y^{'} (x) - 9 x^{2} = 0

整理

y^{'} (x) : y^{'} (x) = 3 x^{2}

若

f^{^{'}} (x) = g (x)

则

f (x) = \int g (x) d x

y = \int 3 x^{2} d x

\int 3 x^{2} d x = x^{3} + c_{1}

y = x^{3} + c_{1}

\frac{\partial}{\partial y} (e^{- 2 x} \cdot cos (2 y))

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