3y^'-9x^2=0

Lösung

3 y^{^{'}} - 9 x^{2} = 0

y = x^{3} + c_{1}

Schritte zur Lösung

3 y^{'} (x) - 9 x^{2} = 0

Isoliere

y^{'} (x) : y^{'} (x) = 3 x^{2}

Wenn

f^{^{'}} (x) = g (x)

dann

f (x) = \int g (x) d x

y = \int 3 x^{2} d x

\int 3 x^{2} d x = x^{3} + c_{1}

y = x^{3} + c_{1}

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