y^'=e^x

Lösung

y^{^{'}} = e^{x}

y = e^{x} + c_{1}

Schritte zur Lösung

y^{'} (x) = e^{x}

Wenn

f^{^{'}} (x) = g (x)

dann

f (x) = \int g (x) d x

y = \int e^{x} d x

\int e^{x} d x = e^{x} + c_{1}

y = e^{x} + c_{1}

\frac{\partial}{\partial y} (\frac{4 y}{x})

\frac{\partial}{\partial y} ((2 x + 3) (y - 2))

\frac{d}{d x} (2 e^{2 x} - e^{- x})

d er i v a t i v e \frac{3}{4} x^{8}

y \to 0 lim (\frac{( 2 x )}{k y})