What is (\partial)/(\partial x)((x^2y^4)(-2.1)) ?

The answer to (\partial)/(\partial x)((x^2y^4)(-2.1)) is -4.2xy^4

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(\partial)/(\partial x)((x^2y^4)(-2.1))

\frac{\partial}{\partial x} ((x^{2} y^{4}) (- 2.1))

- 4.2 x y^{4}

Solution steps

\frac{\partial}{\partial x} ((x^{2} y^{4}) (- 2.1))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= y^{4} (- 2.1) \frac{\partial}{\partial x} (x^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= y^{4} (- 2.1) \cdot 2 x^{2 - 1}

Simplify

= - 4.2 x y^{4}

in v erse l a pl a ce \frac{3}{4 e ^{(2 - t)} sin ( 8 - 4 t )}

\frac{\partial}{\partial x} (y \cdot e^{x})

d er i v a t i v e \frac{800 t}{t + 2}

n = 1 \sum \infty 2^{- n}

d er i v a t i v e - 16 cos (4 t)

What is (\partial)/(\partial x)((x^2y^4)(-2.1)) ?
The answer to (\partial)/(\partial x)((x^2y^4)(-2.1)) is -4.2xy^4