What is the derivative of y=x^{-2} ?

The derivative of y=x^{-2} is -2/(x^3)

What is the first derivative of y=x^{-2} ?

The first derivative of y=x^{-2} is -2/(x^3)

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derivative of

y = x^{- 2}

- \frac{2}{x ^{3}}

Solution steps

\frac{d}{d x} (x^{- 2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= - 2 x^{- 2 - 1}

Simplify

- 2 x^{- 2 - 1} : - \frac{2}{x ^{3}}

= - \frac{2}{x ^{3}}

in v erse l a pl a ce \frac{s + 1}{s ^{2} ( s - 1 )}

\frac{d}{d x} (\frac{x ^{2}}{8})

y^{^{''}} + 8 y^{^{'}} + 12 y = 0

in v erse l a pl a ce \frac{0.5}{( s ^{2} + s + 1 )} \cdot \frac{1}{s}

d er i v a t i v e f (x) = π^{2}

What is the derivative of y=x^{-2} ?
The derivative of y=x^{-2} is -2/(x^3)
What is the first derivative of y=x^{-2} ?
The first derivative of y=x^{-2} is -2/(x^3)