What is (\partial}{\partial x}(\frac{x+y)/z) ?

The answer to (\partial}{\partial x}(\frac{x+y)/z) is 1/z

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial}{\partial x}(\frac{x+y)/z)

\frac{\partial}{\partial x} (\frac{x + y}{z})

\frac{1}{z}

Solution steps

\frac{\partial}{\partial x} (\frac{x + y}{z})

Treat

y, z

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{z} \frac{\partial}{\partial x} (x + y)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{1}{z} (\frac{\partial}{\partial x} (x) + \frac{\partial}{\partial x} (y))

\frac{\partial}{\partial x} (x) = 1

\frac{\partial}{\partial x} (y) = 0

= \frac{1}{z} (1 + 0)

Simplify

= \frac{1}{z}

\int cot (x) csc^{2} (x) d x

\frac{1}{x - 1}, x = 20

\frac{d}{d x} (x - \frac{1}{x ^{2}})

x \to 0 lim (- e^{- x})

\frac{\partial}{\partial x} (2 x + 1 - 5 y)

What is (\partial}{\partial x}(\frac{x+y)/z) ?
The answer to (\partial}{\partial x}(\frac{x+y)/z) is 1/z