What is the tangent of f(x)= 1/(x^4),\at x=-3 ?

The tangent of f(x)= 1/(x^4),\at x=-3 is y= 4/243 x+5/81

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tangent of f(x)= 1/(x^4),\at x=-3

tangent of

f (x) = \frac{1}{x ^{4}}, at x = - 3

y = \frac{4}{243} x + \frac{5}{81}

Solution steps

Find the tangent point:

(- 3, \frac{1}{81})

Find the slope of

f (x) = \frac{1}{x ^{4}} : \frac{df ( x )}{d x} = - \frac{4}{x ^{5}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = \frac{4}{243}

Find the line with slope m=

\frac{4}{243}

and passing through

(- 3, \frac{1}{81}) : y = \frac{4}{243} x + \frac{5}{81}

y = \frac{4}{243} x + \frac{5}{81}

n = 1 \sum \infty (\frac{5}{6})^{n} n

\int 2 \frac{sin ( 2 x )}{sin ( x )} d x

\int (4 x - 3) d x

e^{x}, x = 2

y = \frac{4 81 + x - 3}{x}

What is the tangent of f(x)= 1/(x^4),\at x=-3 ?
The tangent of f(x)= 1/(x^4),\at x=-3 is y= 4/243 x+5/81