en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

area f(x)=2-x^2,g(x)=x

Solution

area

f (x) = 2 - x^{2}, g (x) = x

Solution

\frac{9}{2}

+1

Decimal

4.5

Solution steps

Apply the area formula:

\int_{- 2}^{1} 2 - x^{2} - x d x

Solve

\int_{- 2}^{1} 2 - x^{2} - x d x : \frac{9}{2}

The area is:

= \frac{9}{2}

Graph

Popular Examples

integral of x+1

\int x + 1 d x

d/(d{y)}(({y})/(({x)^2+{y}^2+{z}^2)^{3/2}})

\frac{d}{d y} (\frac{y}{( x ^{2} + y ^{2} + z ^{2} ) ^{\frac{3}{2}}})

integral of (8x^2+4x+9)/(x^3-1)

\int \frac{8 x ^{2} + 4 x + 9}{x ^{3} - 1} d x

tangent of y=x^2,(0,-9)tangent of

y = x^{2}, (0, - 9)

integral of tan(x)sec(2x)

\int tan (x) sec (2 x) d x

Frequently Asked Questions (FAQ)

What is area f(x)=2-x^2,g(x)=x ?
The answer to area f(x)=2-x^2,g(x)=x is 9/2