What is the solution for (3x^2+4xy)dx+(2x^2+2y)dy=0 ?

The solution for (3x^2+4xy)dx+(2x^2+2y)dy=0 is y=-x^2+sqrt(x^4-x^3+c_{1)},y=-x^2-sqrt(x^4-x^3+c_{1)}

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(3x^2+4xy)dx+(2x^2+2y)dy=0

(3 x^{2} + 4 x y) d x + (2 x^{2} + 2 y) d y = 0

y = - x^{2} + x^{4} - x^{3} + c_{1}, y = - x^{2} - x^{4} - x^{3} + c_{1}

Solution steps

(3 x^{2} + 4 x y) d x + (2 x^{2} + 2 y) d y = 0

Solve exact ODE:

y = - x^{2} + x^{4} - x^{3} + c_{1}, y = - x^{2} - x^{4} - x^{3} + c_{1}

y = - x^{2} + x^{4} - x^{3} + c_{1}, y = - x^{2} - x^{4} - x^{3} + c_{1}

d er i v a t i v e f (x) = \frac{4 x}{x - 3}

8 y^{^{'}} - t y = 7

\int_{0}^{5} π (25 - 25 x^{2}) d x

x \to 5 lim (3 x^{2} + 5)

\frac{d}{d x} (\frac{2}{3} x^{2})

What is the solution for (3x^2+4xy)dx+(2x^2+2y)dy=0 ?
The solution for (3x^2+4xy)dx+(2x^2+2y)dy=0 is y=-x^2+sqrt(x^4-x^3+c_{1)},y=-x^2-sqrt(x^4-x^3+c_{1)}