What is the first derivative of 4x+1 ?

The first derivative of 4x+1 is 4

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derivative of 4x+1

derivative of

4 x + 1

4

Solution steps

\frac{d}{d x} (4 x + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4 x) + \frac{d}{d x} (1)

\frac{d}{d x} (4 x) = 4

\frac{d}{d x} (1) = 0

= 4 + 0

Simplify

= 4

\int \frac{1}{8 - 4 sin ( x ) + 7 cos ( x )} d x

\int - x ln (x) d x

\frac{d}{d x} (tan (x))

\frac{d y}{d x} = - \frac{y ln ( y )}{x}

y^{^{'}} = x y - sin (x) e^{- x^{2}} y^{3}