What is the solution for 81y^{''}+90y^'+25y=0 ?

The solution for 81y^{''}+90y^'+25y=0 is y=c_{1}e^{-(5t)/9}+c_{2}e^{-(5t)/9}t

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

81y^{''}+90y^'+25y=0

81 y^{^{''}} + 90 y^{^{'}} + 25 y = 0

y = c_{1} e^{- \frac{5 t}{9}} + c_{2} e^{- \frac{5 t}{9}} t

Solution steps

81 y^{''} (t) + 90 y^{'} (t) + 25 y = 0

Solve linear ODE:

y = c_{1} e^{- \frac{5 t}{9}} + c_{2} e^{- \frac{5 t}{9}} t

y = c_{1} e^{- \frac{5 t}{9}} + c_{2} e^{- \frac{5 t}{9}} t

d er i v a t i v e (5 x^{2} - 10 x + 10) e^{x}

x^{2} y^{^{''}} - 6 y = 0

d er i v a t i v e \frac{1}{x ^{2} - 4}

\int_{0}^{\infty} 2^{- x} d x

d er i v a t i v e f (x) = x (x - 1) (x - 2)

What is the solution for 81y^{''}+90y^'+25y=0 ?
The solution for 81y^{''}+90y^'+25y=0 is y=c_{1}e^{-(5t)/9}+c_{2}e^{-(5t)/9}t