What is the integral from-1 to 1 of 4 ?

The integral from-1 to 1 of 4 is 8

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integral from-1 to 1 of 4

\int_{- 1}^{1} 4 d x

8

Solution steps

\int_{- 1}^{1} 4 d x

Integral of a constant:

\int a d x = a x

= [4 x]_{- 1}^{1}

Compute the boundaries:

8

= 8

\frac{\partial}{\partial x} (ln (6 x^{2} + 7 y^{2} + 7))

\frac{d y}{d x} + tan (x) y = cos^{2} (x)

x \to \infty lim (\frac{x}{2})

\frac{d}{d x} (x^{2} \cdot sin (\frac{1}{x}))

n = 1 \sum \infty \frac{3}{2 n + 3}