What is (\partial)/(\partial x)(8e^{7x-y}) ?

The answer to (\partial)/(\partial x)(8e^{7x-y}) is 56e^{7x-y}

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(\partial)/(\partial x)(8e^{7x-y})

\frac{\partial}{\partial x} (8 e^{7 x - y})

56 e^{7 x - y}

Solution steps

\frac{\partial}{\partial x} (8 e^{7 x - y})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 8 \frac{\partial}{\partial x} (e^{7 x - y})

Apply the chain rule:

e^{7 x - y} \frac{\partial}{\partial x} (7 x - y)

= e^{7 x - y} \frac{\partial}{\partial x} (7 x - y)

\frac{\partial}{\partial x} (7 x - y) = 7

= 8 e^{7 x - y} \cdot 7

Simplify

= 56 e^{7 x - y}

roo t s C e^{x}

f (x) = arcsech (x)

\int t - 5 cos (t) d t

\int \frac{( x - 2 ) ^{3}}{( x - 2 )} d x

\frac{d y}{d x} = 14 x^{8}

What is (\partial)/(\partial x)(8e^{7x-y}) ?
The answer to (\partial)/(\partial x)(8e^{7x-y}) is 56e^{7x-y}